After acidifying with dilute nitric acid, silver nitrate produces a yellow precipitate. It is insoluble in dilute ammonia but dissolves in concentrated ammonia. After acidifying with dilute nitric acid, silver nitrate produces a cream precipitate. AgCl is white and dissolves in dilute ammonia (formation of the diamminesilver(I) complex). One of the problems with using the above test to identify chloride, bromide and iodide ions is that it can be difficult to tell the difference between white, cream and yellow coloured precipitates. However silver iodide is much less affected by light and typically remains yellow under normal laboratory conditions.
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This page discusses the tests for halide ions (fluoride, chloride, bromide and iodide) using silver nitrate and ammonia. AgCl dissolves in dilute ammonia, AgBr does not (but dissolves in concentrated). The correct acid is dilute nitric acid. A white precipitate adrian casino forms, but the student is unsure if chloride was present originally.
Confirming The Precipitate Using Ammonia Solution
Look at the way the solubility products vary from silver chloride to silver iodide. If the actual concentrations of the ions in solution produce a value less than the solubility product, you don't get a precipitate. A precipitate will only form if the concentrations of the ions in solution in water exceed a certain value – different for every different compound. The precipitates are the insoluble silver halides – silver chloride, silver bromide or silver iodide. The chloride gives a white precipitate; the fluoride produces none.